300 J of work is done in sliding a 2 kg block up an inclined plane of height 10m. Taking g = 10 m/s 2 , work done against friction is
Text Solution
Verified by ExpertsThe correct answer is:
B
Net work done in sliding a body up to a height h on inclined plane
= Work done against gravitational force
+ Work done against frictional force
W = W s + W f ... (i)
but W = 300 J
Wg = mgh = 2 × 10 × 10 = 200 J
putting in equation (i), we get
300 = 200 + W f ⇒ W f = 300 – 200 = 100 J
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